Ohms Law Series-Parallel Circuits Calculation Essay Example for Free

Ohms truth Series-Parallel Circuits Calculation EssayTo give the sack up the discussion of Series-Parallel Circuits, I would like to post this last one stay topic which is about Ohms equity of Series-Parallel Circuits for currents and potential differences. I did not even mentioned in my previous topics on how to deal with its currents and voltages regarding this type of circuit connection.Ohms Law in Series-Parallel CircuitsOhms Law in Series-Parallel Circuits CurrentThe issue forth current of the series-parallel circuits depends on the total resistance offered by the circuit when connected across the voltage source. The current flow in the entire circuit and it will divide to flow through parallel kickoffes. In lineament of parallel split up, the current is inversely proportional to the resistance of the branch that is the greater current flows through the least resistance and vice-versa. Then, the current will then sum up again after flowing in various circuit bra nch which is the same as the current source or total current.The total circuit current is the same at each end of a series-parallel circuit, and is equal to the current flow through the voltage source.Ohms Law in Series-Parallel Circuits VoltageThe voltage drop across a series-parallel circuits also go the same way as in series and parallel circuits. In series parts of the circuit, the voltage drop depends on the individual values of the resistors. In parallel parts of the circuit, the voltage across each branch are the same and carries a current depends on the individual values of the resistors.If in elusion of circuit below, the voltage of the series resistance forming a branch of the parallel circuit will divide the voltage across the parallel circuit. If in case of the single resistance in a parallel branch, the voltage across is the same as the sum of the voltages of the seriesresistances.The sum of the voltage across R3 and R4 is the same as the voltage across R2.Finally, the sum of the voltage drop across each paths between the two terminal of the series-parallel circuit is the same as the total voltage applied to the circuit.Lets have a very simple example of this calculation for this topic. Considering the circuit below with its given values, lets calculate the total current, current and voltage drop across each resistances.What is the total current, current and voltage across each resistances Here is the simple calculation of the circuit abovea. Calculate prototypical the total resistance of the circuitThe equivalent resistance for R2 and R3 isR2-3 = 25X50/ 25+50 = 16.67 ohmsR total = 30 ohms + 16.67 ohms = 46.67 ohmsb. Calculate the Total Current using Ohms LawI1 = 120V / 46.67 Ohms = 2.57 Amp. Since R1 is in series connection, the total current is the same for that path.c. Calculating the voltage drop for R1VR1 = 2.57 Amp x 30 ohms = 77.1 voltsd. Calculate the voltage drop across R2 and R3.Since the equivalent resistance for R2 and R3 as calc ulated above is 16.67 ohms, we bay window now calculate the voltage across each branch.VR2 = VR3 = 2.57 Amp x 16.67 ohms = 42. 84 voltse. Finally, we can now calculate the individual current for R2 and R3I2 = VR2 / R2 = 42.84 volts / 25 ohms = 1.71 Amp.I3 = VR3 / R3 = 42.84 volts / 50 ohms = 0.86 Amp.You may also check if the current in each path of the parallel branch are correct by adding its currentsI1 = I2 + I3 = 1.71 Amp + 0.86 Amp = 2.57 Amp. which is the same as calculated above. Therefore, we can say that our answer is correct.